已知关于x的方程x^2+2(a-1)x+a^2-7a-4=0的两根为x1、x2,且满足x1x2-3x1-3x2-2=0.求(1+4/(a^2-4))*(a+2)/a有点看不懂额、没办法才上了两天课,老师就让写这个作业
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![已知关于x的方程x^2+2(a-1)x+a^2-7a-4=0的两根为x1、x2,且满足x1x2-3x1-3x2-2=0.求(1+4/(a^2-4))*(a+2)/a有点看不懂额、没办法才上了两天课,老师就让写这个作业](/uploads/image/z/2831125-13-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8Bx%5E2%2B2%28a-1%29x%2Ba%5E2-7a-4%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B8%BAx1%E3%80%81x2%2C%E4%B8%94%E6%BB%A1%E8%B6%B3x1x2-3x1-3x2-2%3D0.%E6%B1%82%EF%BC%881%2B4%2F%28a%5E2-4%29%EF%BC%89%2A%28a%2B2%29%2Fa%E6%9C%89%E7%82%B9%E7%9C%8B%E4%B8%8D%E6%87%82%E9%A2%9D%E3%80%81%E6%B2%A1%E5%8A%9E%E6%B3%95%E6%89%8D%E4%B8%8A%E4%BA%86%E4%B8%A4%E5%A4%A9%E8%AF%BE%EF%BC%8C%E8%80%81%E5%B8%88%E5%B0%B1%E8%AE%A9%E5%86%99%E8%BF%99%E4%B8%AA%E4%BD%9C%E4%B8%9A)
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