θ是三角形最小内角,且acos²θ/2+sin²θ/2-cos²θ/2-asin²θ/2=a+1,求a的范围
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 14:45:17
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θ是三角形最小内角,且acos²θ/2+sin²θ/2-cos²θ/2-asin²θ/2=a+1,求a的范围
θ是三角形最小内角,且acos²θ/2+sin²θ/2-cos²θ/2-asin²θ/2=a+1,求a的范围
θ是三角形最小内角,且acos²θ/2+sin²θ/2-cos²θ/2-asin²θ/2=a+1,求a的范围
算不出来……