集合A={(x,y)丨x²+mx-y+2=0}集合B={(x,y)丨x-y+1=0,且0≤x≤2}又A∩B≠空集,求实数m的取值
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![集合A={(x,y)丨x²+mx-y+2=0}集合B={(x,y)丨x-y+1=0,且0≤x≤2}又A∩B≠空集,求实数m的取值](/uploads/image/z/2987872-16-2.jpg?t=%E9%9B%86%E5%90%88A%3D%EF%BD%9B%EF%BC%88x%2Cy%EF%BC%89%E4%B8%A8x%26%23178%3B%2Bmx-y%2B2%3D0%EF%BD%9D%E9%9B%86%E5%90%88B%3D%EF%BD%9B%EF%BC%88x%2Cy%EF%BC%89%E4%B8%A8x-y%2B1%3D0%2C%E4%B8%940%E2%89%A4x%E2%89%A42%EF%BD%9D%E5%8F%88A%E2%88%A9B%E2%89%A0%E7%A9%BA%E9%9B%86%2C%E6%B1%82%E5%AE%9E%E6%95%B0m%E7%9A%84%E5%8F%96%E5%80%BC)
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集合A={(x,y)丨x²+mx-y+2=0}集合B={(x,y)丨x-y+1=0,且0≤x≤2}又A∩B≠空集,求实数m的取值
集合A={(x,y)丨x²+mx-y+2=0}集合B={(x,y)丨x-y+1=0,且0≤x≤2}又A∩B≠空集,求实数m的取值
集合A={(x,y)丨x²+mx-y+2=0}集合B={(x,y)丨x-y+1=0,且0≤x≤2}又A∩B≠空集,求实数m的取值
由B:y=x+1 ,0=