5(x-1)^2-2(x+3)^2=3(x+3)^2-7(6x-1)

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5(x-1)^2-2(x+3)^2=3(x+3)^2-7(6x-1)
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5(x-1)^2-2(x+3)^2=3(x+3)^2-7(6x-1)
5(x-1)^2-2(x+3)^2=3(x+3)^2-7(6x-1)

5(x-1)^2-2(x+3)^2=3(x+3)^2-7(6x-1)
5(x-1)^2-2(x+3)^2=3(x+3)^2-7(6x-1)
5x^2-10x+5-2x^2-12x-18=3x^2+18x+27-42x+7
-22x-13=34-24x
2x=47
所以x=47/2

先把左边的两项全部移到右边,而把-7(6x-1)移到左边.
右边提出5,得到:42x-7 = 5[(x+3)^2 - (x-1)^2]
再把右边中括号里的展开,合并同类项,得到:42x-7 = 40x+40
再移项,合并同类项,解出x=23.5