2x+y=6,x-3y=1 求14(x-3y)^2-4(3y-x)^3
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2x+y=6,x-3y=1 求14(x-3y)^2-4(3y-x)^3
2x+y=6,x-3y=1 求14(x-3y)^2-4(3y-x)^3
2x+y=6,x-3y=1 求14(x-3y)^2-4(3y-x)^3
14(x-3y)^2-4(3y-x)^3
=14(x-3y)^2+4(x-3y)^3
=2(x-3y)^2[7+2(x-3y)]
=2×1^2×(7-2×1)
=10
14(x-3y)^2-4(3y-x)^3
=14(x-3y)^2+4(x-3y)^3
=18(x-3y)^2
=18
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