已知x²+y²-2x+4y+5=0求x⁴-y⁴分之2x²+xy-y²乘以2x-y分之xy-y²除以(x²+y²分之y)²的值.
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已知x²+y²-2x+4y+5=0求x⁴-y⁴分之2x²+xy-y²乘以2x-y分之xy-y²除以(x²+y²分之y)²的值.
已知x²+y²-2x+4y+5=0
求x⁴-y⁴分之2x²+xy-y²乘以2x-y分之xy-y²除以(x²+y²分之y)²的值.
已知x²+y²-2x+4y+5=0求x⁴-y⁴分之2x²+xy-y²乘以2x-y分之xy-y²除以(x²+y²分之y)²的值.
由已知得到(x-1)2+(y-2)2=0所以x=1,y=2
x⁴-y⁴分之2x²+xy-y²乘以2x-y分之xy-y²除以(x²+y²分之y)²=(x²+y²)/y=5/2
原式=x2-2x+1+y2+4y+4