[4a^nb^n-1﹙﹣6a^3b^4)+(﹣3a^nb^n)(﹣2ab)^3]÷3ab=

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/08 01:51:54
[4a^nb^n-1﹙﹣6a^3b^4)+(﹣3a^nb^n)(﹣2ab)^3]÷3ab=
x)6IK{Ιw.6K3N3r! QbfqƉI6IEk/}鷅kyxY5] )#M0F1l,@1@@JavM 6<]m 1 Bb̶/.H̳Eԥ

[4a^nb^n-1﹙﹣6a^3b^4)+(﹣3a^nb^n)(﹣2ab)^3]÷3ab=
[4a^nb^n-1﹙﹣6a^3b^4)+(﹣3a^nb^n)(﹣2ab)^3]÷3ab=

[4a^nb^n-1﹙﹣6a^3b^4)+(﹣3a^nb^n)(﹣2ab)^3]÷3ab=
原式=[4a^nb^(n-1)×(-6a³b^4)+(-3a^nb^n)×(-2)³×a³×b³]÷3ab
=[4×(-6)×a^n×a³×b^(n-1)×b^4+(-3)×(-8)×a^n×a³×b^n×b³]÷3ab
=[-24a^(n+3)×b^(n+3)+24a^(n+3)×b^(n+3)]÷3ab
=0÷3ab
=0