6X/(X+1)+2/(X²+2x+1)=6 解方程

(x² +x+1)/(x² +1)+(2x² +x+2)/(x² +x+1) =19/6化成(x² +x+1)/(x² +1)+(x² +1)/(x² +x+1)=13/6急嗷 化简~(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)注意了!是三个分式!(x²+3x+9)/(x²-27)+(6x)/(9x-x²)-(x-1)/(6+2x) xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 x²+2x+2 / x+1=x²+4x+6 / x+2 -1 两个初升高衔接教材的数学题.①(x²+x+1)(x²+x+2)-12=(x²+x+1)(x²+x+1+1)-12=(x²+x+1)²+(x²+x+1)-12=(x²+x-3)(x²+x+5)[十字相乘法]②(x²+x)²-8(x²+x)+12=(x²+x-2)(x²+x-6)[ 已知2x²+2x-3=0 求代数式x(x²-x-1)+2(x²+1)-1/3x(3x²+6x) 一道高一衔接数学思考题,代数,2(X²+6X+1)²+5(X²+1)(X²+6X+1)+2(X²+1)² 2(x²+6x+1)²+5(x²+1)(x²+6x+1)+2(x²+1）²因式分解 3x² - 9x + 2 = 0 x² - 14x = 8 x² + 6x = 1 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy 混合运算6x+2x²-3x+x²+1其中x＝-5 1/X²+3X+2 +1/X²+5X+6 +1/X²+7X+12 +1/X²+9X+20 化简x(x-1)+2x(x+1)-3x(2x-5)我是这一算的，化简x(x-1)+2x(x+1)-3x(2x-5)=x²-x+2x²+2x-6x²+15x=x+2x²-6x²+15x=18x+2x²-6x²=12x²-6x²可以相减吗，还是我算的不对了？ 在实数范围内分解因式 x²+x-1 x²-2x-6 2x²+8x-7 x²-5xy+3y² -2x²-3x+6 4x& 在线求助完全平方公式因式分解(1)-a²-1+2a(2)2x²y-x²-xy²(3)4x²-20x+25(4)(x²+1)²-4x²(5)(2x-y)²-2(2x-y)+1(6)(x+y)²-2(x²-y²)+(x-y)² (x²-4分之x²+x+1)²÷(x三次方-3x²+2x÷x三次方)²×(x÷x+2)² , 试说明不论X取何值代数式（x²+5x²+4x-1)-(-x²-3x+2x²-3)+(8-7x-6x²+x²)的 1.（x-2/x+2+6x/x²-4）×（x²-4）2.(1+x²-1/x²-2x+1)÷1/x-13.x²/x²-y²÷1/x+y+y²/y-x4.（1/x+1-1/1-x²)÷3x/x+1