问几道高二数学、英语题1、设函数f(x)=-x^2+2ex^2-mx+lnx,若方程f(x)=x有解,则实数m的最小值是多少?(要过程)2、He works hard at his lessons in order to catch up with others.=He works hard at his lessons ( ) (
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![问几道高二数学、英语题1、设函数f(x)=-x^2+2ex^2-mx+lnx,若方程f(x)=x有解,则实数m的最小值是多少?(要过程)2、He works hard at his lessons in order to catch up with others.=He works hard at his lessons ( ) (](/uploads/image/z/3136495-31-5.jpg?t=%E9%97%AE%E5%87%A0%E9%81%93%E9%AB%98%E4%BA%8C%E6%95%B0%E5%AD%A6%E3%80%81%E8%8B%B1%E8%AF%AD%E9%A2%981%E3%80%81%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3D-x%5E2%2B2ex%5E2-mx%2Blnx%2C%E8%8B%A5%E6%96%B9%E7%A8%8Bf%28x%29%3Dx%E6%9C%89%E8%A7%A3%2C%E5%88%99%E5%AE%9E%E6%95%B0m%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91%3F%EF%BC%88%E8%A6%81%E8%BF%87%E7%A8%8B%EF%BC%892%E3%80%81He+works+hard+at+his+lessons+in+order+to+catch+up+with+others.%3DHe+works+hard+at+his+lessons+%28++++++%29+%28)
问几道高二数学、英语题1、设函数f(x)=-x^2+2ex^2-mx+lnx,若方程f(x)=x有解,则实数m的最小值是多少?(要过程)2、He works hard at his lessons in order to catch up with others.=He works hard at his lessons ( ) (
问几道高二数学、英语题
1、设函数f(x)=-x^2+2ex^2-mx+lnx,若方程f(x)=x有解,则实数m的最小值是多少?(要过程)
2、He works hard at his lessons in order to catch up with others.
=He works hard at his lessons ( ) ( ) ( ) ( ) catching up wiith others.
=He has caught up with others ( ) ( ) ( ) ( ) his hard working.
3、Now we will have a discussion freely.=Now we will ( ) ( ) ( ) for discussion.
4、Thank you for your timely help.=I ( ) your timely help.=( ) for your timely help.
5、My room is twice larger than his.=My room is ( ) ( ) ( ) larger ( ) his
=My room is three times ( ) ( ) ( ) his.
问几道高二数学、英语题1、设函数f(x)=-x^2+2ex^2-mx+lnx,若方程f(x)=x有解,则实数m的最小值是多少?(要过程)2、He works hard at his lessons in order to catch up with others.=He works hard at his lessons ( ) (
1.由f(x)=x得:x^2+2ex^2-(m+1)x+lnx=0有解,设g(x)=x^2+2ex^2-(m+1)x+lnx (x>0) 对g(x)求导得:g'(x)=2(2e+1)x+1/x-(m+1) 则对g'(x)=0对x>0恒有解,即:2(2e+1)x^2-(m+1)x+1=0对x>0恒成立,所以可得:(m+1)^2-4*2(2e+1)》0所以m的最小值为:根号8(2e+1) -1