高二数学题 设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求C设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求CR(A并B)
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![高二数学题 设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求C设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求CR(A并B)](/uploads/image/z/3138549-69-9.jpg?t=%E9%AB%98%E4%BA%8C%E6%95%B0%E5%AD%A6%E9%A2%98+%E8%AE%BE%E5%85%A8%E9%9B%86%E4%B8%BAR%2C%E9%9B%86%E5%90%88A%EF%BC%9D%7Bx%7Clog1%2F2%283-x%29%E2%89%A5-2%7D%2CB%3D%7Bx%7C5%2F%28x%2B2%29%E2%89%A51%7D%2C%E6%B1%82C%E8%AE%BE%E5%85%A8%E9%9B%86%E4%B8%BAR%2C%E9%9B%86%E5%90%88A%EF%BC%9D%7Bx%7Clog1%2F2%283-x%29%E2%89%A5-2%7D%2CB%3D%7Bx%7C5%2F%28x%2B2%29%E2%89%A51%7D%2C%E6%B1%82CR%28A%E5%B9%B6B%EF%BC%89)
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高二数学题 设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求C设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求CR(A并B)
高二数学题 设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求C
设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求CR(A并B)
高二数学题 设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求C设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求CR(A并B)
A;log1/2(3-x)≥log1/2(1/2^-2),因为它是减函数所以3-x≥.,1/2^-2,即3-x≥4,所以-1≥x,又因3-x>0,所以3>x
B:当2+x>0时,则5>=x+2.当2+x
由集合A={x|log1/2(3-x)≥-2}可得,
方程组log1/2(3-x)≥-2
(3-x)>0
解得-1<=(少于或等于的意思)x<3
集合B不等式5/(x+2)≥1,
由不等式右边可知,x+2>0,x>-2
所以5/(x+2)≥1
5≥x+2
x<=3
即是-2
高二数学题 设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求C设全集为R,集合A={x|log1/2(3-x)≥-2},B={x|5/(x+2)≥1},求CR(A并B)
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