已知碳酸氢钠不稳定,受热易分解(2NaHCO3加热生成Na2CO3+H2O+CO2),现取Na2CO3和NaHCO3的混合物40g,加热到质量不再改变为止,剩余固体质量为27.6g,下列说法正确的是1.反应后生成CO2的质量为12.4g2.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 02:40:31
![已知碳酸氢钠不稳定,受热易分解(2NaHCO3加热生成Na2CO3+H2O+CO2),现取Na2CO3和NaHCO3的混合物40g,加热到质量不再改变为止,剩余固体质量为27.6g,下列说法正确的是1.反应后生成CO2的质量为12.4g2.](/uploads/image/z/3157243-43-3.jpg?t=%E5%B7%B2%E7%9F%A5%E7%A2%B3%E9%85%B8%E6%B0%A2%E9%92%A0%E4%B8%8D%E7%A8%B3%E5%AE%9A%2C%E5%8F%97%E7%83%AD%E6%98%93%E5%88%86%E8%A7%A3%282NaHCO3%E5%8A%A0%E7%83%AD%E7%94%9F%E6%88%90Na2CO3%2BH2O%2BCO2%29%2C%E7%8E%B0%E5%8F%96Na2CO3%E5%92%8CNaHCO3%E7%9A%84%E6%B7%B7%E5%90%88%E7%89%A940g%2C%E5%8A%A0%E7%83%AD%E5%88%B0%E8%B4%A8%E9%87%8F%E4%B8%8D%E5%86%8D%E6%94%B9%E5%8F%98%E4%B8%BA%E6%AD%A2%2C%E5%89%A9%E4%BD%99%E5%9B%BA%E4%BD%93%E8%B4%A8%E9%87%8F%E4%B8%BA27%EF%BC%8E6g%2C%E4%B8%8B%E5%88%97%E8%AF%B4%E6%B3%95%E6%AD%A3%E7%A1%AE%E7%9A%84%E6%98%AF1%EF%BC%8E%E5%8F%8D%E5%BA%94%E5%90%8E%E7%94%9F%E6%88%90CO2%E7%9A%84%E8%B4%A8%E9%87%8F%E4%B8%BA12%EF%BC%8E4g2%EF%BC%8E)
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