已知二次函数y=(m+1)x^2/2-(3m+1)x/2+m,且与y轴交点的纵坐标为m,m≠1若二次函数的图像截直线y=-x+1所得直线的长为2√2,确定m的值
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![已知二次函数y=(m+1)x^2/2-(3m+1)x/2+m,且与y轴交点的纵坐标为m,m≠1若二次函数的图像截直线y=-x+1所得直线的长为2√2,确定m的值](/uploads/image/z/3171820-4-0.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3D%28m%2B1%29x%5E2%2F2-%283m%2B1%29x%2F2%2Bm%2C%E4%B8%94%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E7%82%B9%E7%9A%84%E7%BA%B5%E5%9D%90%E6%A0%87%E4%B8%BAm%2Cm%E2%89%A01%E8%8B%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E7%9A%84%E5%9B%BE%E5%83%8F%E6%88%AA%E7%9B%B4%E7%BA%BFy%3D-x%2B1%E6%89%80%E5%BE%97%E7%9B%B4%E7%BA%BF%E7%9A%84%E9%95%BF%E4%B8%BA2%E2%88%9A2%2C%E7%A1%AE%E5%AE%9Am%E7%9A%84%E5%80%BC)
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