已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an

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已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an
已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an

已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an
an+1=an+1/n的平方+n
an+1-an=1/n^2+n
an+1-an=1/n(n+1)
an+1-an=(1/n)-1/(n+1)
an-an-1=(1/n-1)-1/n
an-1-an-2=(1/n-2)-1/(n-1)
.
a2-a1=1/1-1/2
an-a1=1-1/n
an=1-1/n+1/2
an=3/2-1/n

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