已知函数f(x)=sin(2x+π/3)+sin(2x-π/3)+2cos²x-1,x∈R (1)求函数f(x)的最小正周期 (2)求函数f(x)在区间【-π/4,π/4】上的最大值和最小值
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![已知函数f(x)=sin(2x+π/3)+sin(2x-π/3)+2cos²x-1,x∈R (1)求函数f(x)的最小正周期 (2)求函数f(x)在区间【-π/4,π/4】上的最大值和最小值](/uploads/image/z/325261-37-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dsin%EF%BC%882x%2B%CF%80%2F3%EF%BC%89%2Bsin%EF%BC%882x-%CF%80%2F3%EF%BC%89%2B2cos%26%23178%3Bx-1%2Cx%E2%88%88R+%EF%BC%881%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F+%EF%BC%882%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E5%9C%A8%E5%8C%BA%E9%97%B4%E3%80%90-%CF%80%2F4%2C%CF%80%2F4%E3%80%91%E4%B8%8A%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC)
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