解方程:﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49解方程:1.﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=492.﹙x²-x+1﹚﹙x²-x+2﹚=123.x²+2﹙√2-1﹚x+3-2√2=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 20:46:31
解方程:﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49解方程:1.﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=492.﹙x²-x+1﹚﹙x²-x+2﹚=123.x²+2﹙√2-1﹚x+3-2√2=0
解方程:﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49
解方程:1.﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49
2.﹙x²-x+1﹚﹙x²-x+2﹚=12
3.x²+2﹙√2-1﹚x+3-2√2=0
解方程:﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49解方程:1.﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=492.﹙x²-x+1﹚﹙x²-x+2﹚=123.x²+2﹙√2-1﹚x+3-2√2=0
﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49
(x^2-2x-15)+(x^2+2x-8)=49
2x^2-23=49
x^2=36
x1=6,x2=-6
﹙x²-x+1﹚﹙x²-x+2﹚=12
﹙x²-x+1﹚﹙x²-x+1+1﹚=12
﹙x²-x+1﹚^2+﹙x²-x+1﹚-12=0
﹙x²-x+1+4﹚﹙x²-x+1-3﹚=0
﹙x²-x+5﹚﹙x²-x-2﹚=0
则 (x-2)(x+1)=0
x1=2,x2=-1
x²+2﹙√2-1﹚x+3-2√2=0
x²+2﹙√2-1﹚x+(√2-1)^2=0
(x+√2-1)^2=0
x=1-√2
x^2-2x-15+x^2+2x-8=49 2x^2-72=0 x=+-6 设y=x^2-x+1 y*(y+1)=12 y1=-4 y2=3 x1=2 x2=-1 y=-4时无解 3-2√2=﹙√2-1﹚^2 易得原方程为( x+√2-1)^2=0
1. ﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49
x^2-2x-15+(x^2+2x-8)=49
2x^2=72
x^2=36
x=6 或 x=-6.
2.﹙x²-x+1﹚﹙x²-x+2﹚=12
(x^2-x+1)[(x^2-x+1)+1]=12
(x^2-x+1)^2+(x^2-x+1)-12=0
[(x^...
全部展开
1. ﹙x-5﹚﹙x+3﹚+﹙x-2﹚﹙x+4﹚=49
x^2-2x-15+(x^2+2x-8)=49
2x^2=72
x^2=36
x=6 或 x=-6.
2.﹙x²-x+1﹚﹙x²-x+2﹚=12
(x^2-x+1)[(x^2-x+1)+1]=12
(x^2-x+1)^2+(x^2-x+1)-12=0
[(x^2-x+1)+4]*[(x^2-x+1)-3]=0
(x^2-x+5)(x^2-x-2)=0
(x^2-x+5)(x-2)(x+1)=0
x=2 或 x=-1
3.x²+2﹙√2-1﹚x+3-2√2=0
(x+√2-1)^2+3-2√2-(√2-1)^2=0
(x+√2-1)^2=0
x=1-√2
收起