Tn=log2[2^1]+log2[2^(-2)]+...+log[2^(4-3n)] =1-2-5+.+4-3n =(1+4-3n)*3n/2 疑问：项数为什么是3n?

log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 (log2 9)/(log2 8) = 2/3(log2 3) log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ 解方程log2(2-x)=log2(x-1)+1 解2log2^(x-5)=log2^(x-1)+1 求解log2(3x)=log2(2x+1) 2log2 10—log2 25=? |[log2(x)]^2-3log2(x)+1| (log2)2+log2*log50+1g25值 log2 1+ log2 2+ … + log2 n >= ⌊n/2」log2 (n/2) 求证明,2是底 log2(根号下7/48)+log2(12)-1/2log2(42)-1=? log2根号7/48+log2^12-1/2log2^42-1= =[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊 2log2^3=