log2(根号下7/48)+log2(12)-1/2log2(42)-1=?

log2(根号下7/48)+log2(12)-1/2log2(42)-1=? 求化简log2根号下48分之7+log2 12-log2 42 log2根号7/48+log2^12-1/2log2^42-1= log2 SQR(7/48)+log2 12 -1/2log2 48 log2 SQR(7/48)+log2 12 -1/2log2 42 根号下[(log2^3)^2-4log2^3+4]+log2^(1/3) 根号下{[log2 （5)]^2-4log2(5)+4}+log2(1/5) 计算 根号下[(log2 5)^2-4log2 5+4]+log2 1/5 化简根号下[(log2^3)^2-4log2^3+4]+log2^(1/3) f(x)=log2^根号下1+sinx + log2^根号下1-sinx 的定义域值域 log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙! log2为底数根号7/48为真数+log2为底数12为真数-1/2log2为底数42为真数=? 1/2log2(7/48)+log2 12-1/2log2 42log2 的2 在g的右下脚 化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3 求值：log2√(7/48)+log2(12)-1/2log2(42)-1 这道题我算来算去算不对 计算log2 √(48/7)-log2 12+(1/2)log2 42-1 log2[√(7/48)]+log2(12)-log2(√42) y=根号下log2(x-1)的定义域