{5x-3y+z=2,5x+2y-4z=3,-5x+y-z=2}解方程组 {x-y-z=-1,3x+5y+7z=11,4x-y+2z=-1}解方程组

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{5x-3y+z=2,5x+2y-4z=3,-5x+y-z=2}解方程组 {x-y-z=-1,3x+5y+7z=11,4x-y+2z=-1}解方程组
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{5x-3y+z=2,5x+2y-4z=3,-5x+y-z=2}解方程组 {x-y-z=-1,3x+5y+7z=11,4x-y+2z=-1}解方程组
{5x-3y+z=2,5x+2y-4z=3,-5x+y-z=2}解方程组 {x-y-z=-1,3x+5y+7z=11,4x-y+2z=-1}解方程组

{5x-3y+z=2,5x+2y-4z=3,-5x+y-z=2}解方程组 {x-y-z=-1,3x+5y+7z=11,4x-y+2z=-1}解方程组
{5x-3y+z=2,5x+2y-4z=3,-5x+y-z=2
5x-3y+z=2 ①
5x+2y-4z=3 ②
-5x+y-z=2 ③
①-②得 -5y+5z=-1 ④
①+③得 -2y=4 ⑤ 得y=-2
代入y到④,得z=-11/5
代入y和z到①,得x=-9/25
因此 x=-9/25 y=-2 z=-11/5
{x-y-z=-1,3x+5y+7z=11,4x-y+2z=-1}
x-y-z=-1 ①
3x+5y+7z=11 ②
4x-y+2z=-1 ③
3*①-②得 -8y-10z=-14 ④
4*①-③得 -3y-6z=-3 ⑤
3*④-8*⑤得 18z=-18 z=-1
代入z到④,得y=3
代入y和z到①,得x=1
因此 x=1 y=3 z=-1
o(∩_∩)o

初一的，解方程组，找书，书上有详细的解答过程

这么简单的代入消元法都不会？无语

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? x/2=y/3=z/5 x+3y-z/x-3y+z 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x+y=5 2x+3y-z=9 x-y+z=4 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. 已知：4x-5y+2z=0 x+4y-3z=0则：(x*x+y*y+z*z)/(x*y+y*z+z*x)=____. ｛ 5x-3y+z=25x+2y-4z=3-5x+y-z=2 x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5 x:y:z=3:4:5 2x-3y+2z=8 x-y-2z=? 已知(x+2y)/3=(y+3z)/4=(z+5x)/5,则x:y:z= 已知x+2y/3=y+3z/4=z+5x/5,则x:y:z=? 已知x+2y/3=y+3z/4=z+5x/5,则x:y:z= x+y+z=4 2x-y+z=3 3x-2y-3z=-5 3x-2y+z=4 x+y-z=5 4x-4y+3z=27 3x-y+2z=-1 4x+y+z=5 x-2y-z=-2 x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快 若x/2=y/3=z/4,则3x-2y+5z/x+y+z=