已知x+y=3xy,求2x+2y-xy/x+y+2xy的值、
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已知x+y=3xy,求2x+2y-xy/x+y+2xy的值、
已知x+y=3xy,求2x+2y-xy/x+y+2xy的值、
已知x+y=3xy,求2x+2y-xy/x+y+2xy的值、
x+y=3xy,
所以
2x+2y-xy/x+y+2xy
=(2×3xy-xy)/(3xy+2xy)
=5/5
=1
原式=[2(x+y)-xy]/[(x+y)+2xy]
=[2(3xy)-xy]/[(3xy)+2xy]
=5xy/5xy
=1
2x+2y-xy/x+y+2xy
=[2(x+y)-xy]/[(x+y)+2xy]
=1
原式=[2(x+y)-xy]/[(x+y)+2xy]
=[2(3xy)-xy]/[(3xy)+2xy]
=5xy/5xy
=1
1
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