1/1*3+1/3*5+1/5*7+1/7*9+.1/2009*2011+1/2011*2013 等于多少?
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1/1*3+1/3*5+1/5*7+1/7*9+.1/2009*2011+1/2011*2013 等于多少?
1/1*3+1/3*5+1/5*7+1/7*9+.1/2009*2011+1/2011*2013 等于多少?
1/1*3+1/3*5+1/5*7+1/7*9+.1/2009*2011+1/2011*2013 等于多少?
1/[n*(n+2)]=[1/n-1/(n+2)]/2,
所以原式=(1-1/3+1/3-1/5+1/5-1/7+……+1/2009-1/2011)/2=(1-1/2013)/2=1006/2013
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1/[n*(n+2)]=[1/n-1/(n+2)]/2,
所以原式=(1-1/3+1/3-1/5+1/5-1/7+……+1/2009-1/2011)/2=(1-1/2013)/2=1006/2013
~如果你认可我的回答,请及时点击【采纳为满意回答】按钮~
~手机提问的朋友在客户端右上角评价点【满意】即可。
~你的采纳是我前进的动力~~
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1-3+5-7+...
(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简算(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简便计算
1/1*3+1/1*3*5+1/1*3*5*7+1/1*3*5*7*9-73/945
1/3+1/5+1/7+.+1/2n+1
(1/3+1/5+1/7)*(1/5+1/7+1/9)-(1/3+1/5+1/7+1/9)*(1/5+1/7)=?
1 1 1 1 1 3 5 7 1 5 13 25 1 7 25 why
1/1×3+1/3×5+1/5×7+1/7×9.+1/2011×2013
简算:1/1*3+1/3*5+1/5*7+1/7*9+1/9*11
1/1*3+1/3*5+1/5*7+1/7*9+...1/17*19=
计算1/(1×3)+1/(3×5)+1/(5×7)+1/(7×9)+.+1/(19×21)
1/1×3+1/3×5+1/5×7+1/7×9+.+1/2013×2015
1/1*3+1/3*5+1/5*7+1/7*9+.+1/101*103
帮帮忙1/1*3+1/3*5+1/5*7+1/7*9+...1/99*101
1/1*3+1/3*5+1/5*7+1/7*9+1/49*51=
计算:1/1×3+1/3×5+1/5×7+1/7×9``````+1/2001×2003
(1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1
1/1*3+1/3*5+1/5*7+1/7*9+1/9*11
(1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1