G为△ABC所在平面内一点且满足向量GA+向量GB+向量GC=0向量,求证G为△ABC的重心.顺便帮我作图回答,而且要很详细的那种
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![G为△ABC所在平面内一点且满足向量GA+向量GB+向量GC=0向量,求证G为△ABC的重心.顺便帮我作图回答,而且要很详细的那种](/uploads/image/z/3488209-25-9.jpg?t=G%E4%B8%BA%E2%96%B3ABC%E6%89%80%E5%9C%A8%E5%B9%B3%E9%9D%A2%E5%86%85%E4%B8%80%E7%82%B9%E4%B8%94%E6%BB%A1%E8%B6%B3%E5%90%91%E9%87%8FGA%2B%E5%90%91%E9%87%8FGB%2B%E5%90%91%E9%87%8FGC%3D0%E5%90%91%E9%87%8F%2C%E6%B1%82%E8%AF%81G%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E9%87%8D%E5%BF%83.%E9%A1%BA%E4%BE%BF%E5%B8%AE%E6%88%91%E4%BD%9C%E5%9B%BE%E5%9B%9E%E7%AD%94%2C%E8%80%8C%E4%B8%94%E8%A6%81%E5%BE%88%E8%AF%A6%E7%BB%86%E7%9A%84%E9%82%A3%E7%A7%8D)
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