已知函数f(x)满足对任意实数x,y都由f(x+y)=f(x)+f(y)+xy+1,且f(—2)=—2(1)求f(1)的值(2)证明:对于一切大于1的正整数t,都由f(t)>t(3)试求满足f(t)=t的整数的个数,并说明理由
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![已知函数f(x)满足对任意实数x,y都由f(x+y)=f(x)+f(y)+xy+1,且f(—2)=—2(1)求f(1)的值(2)证明:对于一切大于1的正整数t,都由f(t)>t(3)试求满足f(t)=t的整数的个数,并说明理由](/uploads/image/z/3504179-11-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%E6%BB%A1%E8%B6%B3%E5%AF%B9%E4%BB%BB%E6%84%8F%E5%AE%9E%E6%95%B0x%2Cy%E9%83%BD%E7%94%B1f%28x%2By%29%3Df%28x%29%2Bf%28y%29%2Bxy%2B1%2C%E4%B8%94f%28%E2%80%942%29%3D%E2%80%942%EF%BC%881%EF%BC%89%E6%B1%82f%EF%BC%881%EF%BC%89%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E8%AF%81%E6%98%8E%EF%BC%9A%E5%AF%B9%E4%BA%8E%E4%B8%80%E5%88%87%E5%A4%A7%E4%BA%8E1%E7%9A%84%E6%AD%A3%E6%95%B4%E6%95%B0t%2C%E9%83%BD%E7%94%B1f%28t%29%3Et%283%29%E8%AF%95%E6%B1%82%E6%BB%A1%E8%B6%B3f%EF%BC%88t%EF%BC%89%3Dt%E7%9A%84%E6%95%B4%E6%95%B0%E7%9A%84%E4%B8%AA%E6%95%B0%2C%E5%B9%B6%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
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