先化简,再求值,﹙1/x-y-1/x+y﹚÷2y/x²+2xy+y²,其中x=√3+√2,y=√3-√2
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![先化简,再求值,﹙1/x-y-1/x+y﹚÷2y/x²+2xy+y²,其中x=√3+√2,y=√3-√2](/uploads/image/z/3507760-64-0.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BC%2C%EF%B9%991%2Fx-y-1%2Fx%2By%EF%B9%9A%C3%B72y%2Fx%26%23178%3B%2B2xy%2By%26%23178%3B%2C%E5%85%B6%E4%B8%ADx%3D%E2%88%9A3%2B%E2%88%9A2%2Cy%3D%E2%88%9A3-%E2%88%9A2)
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先化简,再求值,﹙1/x-y-1/x+y﹚÷2y/x²+2xy+y²,其中x=√3+√2,y=√3-√2
先化简,再求值,﹙1/x-y-1/x+y﹚÷2y/x²+2xy+y²,其中x=√3+√2,y=√3-√2
先化简,再求值,﹙1/x-y-1/x+y﹚÷2y/x²+2xy+y²,其中x=√3+√2,y=√3-√2
即x+y=2√3
x-y=2√2
原式=(x+y-x+y)/(x+y)(x-y)÷2y/(x+y)²
=2y/(x+y)(x-y)*(x+y)²/2y
=(x+y)/(x-y)
=2√3/2√2
=√6/2
原式=x²/[xy(x+y)]-y²/[xy(x+y)]
=(x²-y²)/[xy(x+y)]
=(x+y)/(x-y)/[xy(x+y)]
=(x-y)/(xy)
=[(√2+1)-(√2-1)]/[(√2+1)(√2-1)]
=(√2+1-√2+1)/(√2²-1²)
=2/(2-1)
=2
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