用maple解方程2ab+2bc+2cd+2de-e^2=-3057944299725842ac+2bd+2ce-2de-a^2=-10570858937036782ad+2be-2ab-2ce-d^2=-6316450970317212ae-2ac-2be-2cd-b^2=-5467406632805072ad+2ae+2bc+2bd+c^2=1626797122752585只要一组解,这组解满足a^2+b^2+c^2+d^2+e^2=4

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用maple解方程2ab+2bc+2cd+2de-e^2=-3057944299725842ac+2bd+2ce-2de-a^2=-10570858937036782ad+2be-2ab-2ce-d^2=-6316450970317212ae-2ac-2be-2cd-b^2=-5467406632805072ad+2ae+2bc+2bd+c^2=1626797122752585只要一组解,这组解满足a^2+b^2+c^2+d^2+e^2=4
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用maple解方程2ab+2bc+2cd+2de-e^2=-3057944299725842ac+2bd+2ce-2de-a^2=-10570858937036782ad+2be-2ab-2ce-d^2=-6316450970317212ae-2ac-2be-2cd-b^2=-5467406632805072ad+2ae+2bc+2bd+c^2=1626797122752585只要一组解,这组解满足a^2+b^2+c^2+d^2+e^2=4
用maple解方程
2ab+2bc+2cd+2de-e^2=-305794429972584
2ac+2bd+2ce-2de-a^2=-1057085893703678
2ad+2be-2ab-2ce-d^2=-631645097031721
2ae-2ac-2be-2cd-b^2=-546740663280507
2ad+2ae+2bc+2bd+c^2=1626797122752585
只要一组解,这组解满足a^2+b^2+c^2+d^2+e^2=473051369520767

用maple解方程2ab+2bc+2cd+2de-e^2=-3057944299725842ac+2bd+2ce-2de-a^2=-10570858937036782ad+2be-2ab-2ce-d^2=-6316450970317212ae-2ac-2be-2cd-b^2=-5467406632805072ad+2ae+2bc+2bd+c^2=1626797122752585只要一组解,这组解满足a^2+b^2+c^2+d^2+e^2=4
从上到下分别为(1)式,(2)式.(6)式
则(5)-(1)-(2)-(3)-(4),左=a^2+b^2+c^2+d^2+e^2,但是右不等于473051369520767(只需看个位即可),所以不存在这样一组解可以满足(6)

用maple解方程2ab+2bc+2cd+2de-e^2=-3057944299725842ac+2bd+2ce-2de-a^2=-10570858937036782ad+2be-2ab-2ce-d^2=-6316450970317212ae-2ac-2be-2cd-b^2=-5467406632805072ad+2ae+2bc+2bd+c^2=1626797122752585只要一组解,这组解满足a^2+b^2+c^2+d^2+e^2=4 用maple解方程2ab+2bc+2cd+2de-e^2=-5780613042962ac+2bd+2ce-2de-a^2=-1998272010782-2ab+2ad+2be-2ce-d^2=-1194036100249-2ac+2ae-2be-2cd-b^2=-10335362254832ad+2ae+2bc+2bd+c^2=3075230855865好像有整数解 maple 解方程1436+0.0603*1500^2/x = ln(2102/x)这个该怎么用maple解呃……算出来了 用maple solve 解方程,求高手啊我用maple 的solve 解方程 ,比如说方程E=3a+2(b/c)现在我要解方程E求（b/c）这个整体,怎么用maple输入指令啊,求大神啊,急! maple函数解不等式我用指令r=maple('solve(exp(-pi*x/sqrt(1-x^2)) 怎么用maple解微积分方程 MAPLE画三维图形用maple画z=x^2+y^2在0 解方程：ab=1,bc=2,cd=3,de=4,ea=5. 解方程：①{ab+c+d=3 bc+d+a=5 cd+a+b=2 da+b+c=6 ab+c+d=3,bc+a+d=5,cd+a+b=2,da+b+c=6 解方程 利用matlab 计算四杆机构通过方程matlab计算,假设AD=BC=600mm,AB=200mm(AB+BC)^2=AD^2+CD^2-2AD*CD*COSa(BC-AB)^2=AD^2+CD^2-2*AD*CD*COSba-b=60求AB和CD的长度.分别列出a,b角度和CD杆长度的各个计算数值.参考：[a,b,CD]=solv 如图,已知AB//DC,AD//BC.证明:(1)AB=CD;(2)AD=BC 如图已知AB//DC AD//BC 证明 1 AB=CD 2AD=BC 直角梯形ABCD AB平行CD AD垂直CD AB=1 AD=2 CD=4 BC=?直角梯形ABCD AB平行CD AD垂直CD AB=1 AD=2 CD=4 BC=? 如图所示,已知AB:BC:CD=3:2:4,E、F分别是AB,CD的中点,且EF=22CM,求AB,BC,CD的长 已知,AB：BC：CD=3:2:4,E、F分别是AB和CD的中点,EF=22cm,求AB,BC,CD的长度. 梯形ABCD中,AB平行于CD,AD=BC ,CD=2AB,求证BD垂直于BC= =AD=BC=AB BC是线段AD上的两点,且CD=2分之3AB,AC=35厘米,BD=44厘米,侧AD等于多少厘米?用因为 +所以解,不要方程