数学高手来解几道一元2次方程一,公式法解1,x^2+2x-2=02,2x^2+1=2又根号3二,用分解因式解1,(x+2)(x-4)=02,4x(2x+1)=3(2x+1)3,(4x-1)(5x+7)=04,3x(x-1)=2-2x5,(2x+3)^2=4(2x+3)6,2(x-3)^2=x^2-9解下列方程1,5(x^2-x)=3(x^2+x)2,(x-2)^
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![数学高手来解几道一元2次方程一,公式法解1,x^2+2x-2=02,2x^2+1=2又根号3二,用分解因式解1,(x+2)(x-4)=02,4x(2x+1)=3(2x+1)3,(4x-1)(5x+7)=04,3x(x-1)=2-2x5,(2x+3)^2=4(2x+3)6,2(x-3)^2=x^2-9解下列方程1,5(x^2-x)=3(x^2+x)2,(x-2)^](/uploads/image/z/3616060-4-0.jpg?t=%E6%95%B0%E5%AD%A6%E9%AB%98%E6%89%8B%E6%9D%A5%E8%A7%A3%E5%87%A0%E9%81%93%E4%B8%80%E5%85%832%E6%AC%A1%E6%96%B9%E7%A8%8B%E4%B8%80%2C%E5%85%AC%E5%BC%8F%E6%B3%95%E8%A7%A31%2Cx%5E2%2B2x-2%3D02%2C2x%5E2%2B1%3D2%E5%8F%88%E6%A0%B9%E5%8F%B73%E4%BA%8C%2C%E7%94%A8%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%E8%A7%A31%2C%EF%BC%88x%2B2%29%28x-4%29%3D02%2C4x%282x%2B1%29%3D3%282x%2B1%293%2C%284x-1%29%285x%2B7%29%3D04%2C3x%28x-1%29%3D2-2x5%2C%282x%2B3%29%5E2%3D4%282x%2B3%296%2C2%28x-3%29%5E2%3Dx%5E2-9%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B1%2C5%28x%5E2-x%29%3D3%28x%5E2%2Bx%292%2C%28x-2%29%5E)
数学高手来解几道一元2次方程一,公式法解1,x^2+2x-2=02,2x^2+1=2又根号3二,用分解因式解1,(x+2)(x-4)=02,4x(2x+1)=3(2x+1)3,(4x-1)(5x+7)=04,3x(x-1)=2-2x5,(2x+3)^2=4(2x+3)6,2(x-3)^2=x^2-9解下列方程1,5(x^2-x)=3(x^2+x)2,(x-2)^
数学高手来解几道一元2次方程
一,公式法解
1,x^2+2x-2=0
2,2x^2+1=2又根号3
二,用分解因式解
1,(x+2)(x-4)=0
2,4x(2x+1)=3(2x+1)
3,(4x-1)(5x+7)=0
4,3x(x-1)=2-2x
5,(2x+3)^2=4(2x+3)
6,2(x-3)^2=x^2-9
解下列方程
1,5(x^2-x)=3(x^2+x)
2,(x-2)^2=(2x+3)^2
3,2y^+4y=y+2
4,2x+6=(x+3)^2
5,(x-2)(x-3)=12
到时候在+分
数学高手来解几道一元2次方程一,公式法解1,x^2+2x-2=02,2x^2+1=2又根号3二,用分解因式解1,(x+2)(x-4)=02,4x(2x+1)=3(2x+1)3,(4x-1)(5x+7)=04,3x(x-1)=2-2x5,(2x+3)^2=4(2x+3)6,2(x-3)^2=x^2-9解下列方程1,5(x^2-x)=3(x^2+x)2,(x-2)^
1.x^2+2x-2=0
△=b^2-4ac=4+8=12
b^2加减△
-------= -2-根号3 或 -2+根号3
2a
2.2x^2+1=2又根号3
2x^2+(1-2又根号3)=0
△=b^2-4ac=16又根号3-8
b^2加减△
------- 约等于 -1.1
2a
二,用分解因式解
1,(x+2)(x-4)=0
x=-2 x=4
2,4x(2x+1)=3(2x+1)
4x(2x+1)-3(2x+1)=0
(2x-1)(4x-3)=0
x=二分之一 x=四分之三
3,(4x-1)(5x+7)=0
x=四分之一 x=负五分之七
4,3x(x-1)=2-2x
3x(x-1)=-2(x-1)
3x(x-1)+2(x-1)=0
(x-1)(3x+2)=0
x=1 x=负三分之二
5,(2x+3)^2=4(2x+3)
4x^2+12x+9=8x+12
4x^2+4x-3=0
x=二分之一 x=负二分之三
6,2(x-3)^2=x^2-9
(x-3)(x-9)=0
x=3 x=9
解下列方程
1,5(x^2-x)=3(x^2+x)
用提公因式解
2,(x-2)^2=(2x+3)^2
3,2y^2+4y=y+2
4,2x+6=(x+3)^2
5,(x-2)(x-3)=12
x=2 x=3