{int n=2,k=0; while(k++&&n++>2); printf("%d %d\n",k,n);为什么答案是1,k++&&n++>2中'>'的优先级不是高于“&&”么?为什么不会先算n++>2
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{int n=2,k=0; while(k++&&n++>2); printf("%d %d\n",k,n);为什么答案是1,k++&&n++>2中'>'的优先级不是高于“&&”么?为什么不会先算n++>2
{int n=2,k=0; while(k++&&n++>2); printf("%d %d\n",k,n);为什么答案是1,k++&&n++>2中'>'的优先级不是高于“&&”么?为什么不会先算n++>2
{int n=2,k=0; while(k++&&n++>2); printf("%d %d\n",k,n);为什么答案是1,k++&&n++>2中'>'的优先级不是高于“&&”么?为什么不会先算n++>2
while(k++&&n++>2);中,k=0,所以第一次执行循环的时候就停止了,而k++的效果就是运行之后才加1,因此n++>2这个根本就没有判断
int k=0,n=2; while(k++&&n++>2);什么意思?请说明.int k=0,n=2;while(k++&&n++>2)
int k=0;while(k++
int main(void) { int k=0; while(k++
while(n++>2);是否相当于while(n>2){n++;}?#includemain(){int n=2,k=0;while(k++&&n++>2);printf(%d,%d,k,n);}输出的结果是?
int n=0; while(n++
int n=0; while(n++
int n=0;while(n++
main() {int k=0; while(printf(*)) {k++; if(k
int k=2; while(k==0) printf(%d,k); k--; printf(
);下列循环的循环次数为0,为什么,求详解
.程序段如下 int k=0; while(k++
int m=3,n=6,k=0; while(m++
{int n=2,k=0; while(k++&&n++>2); printf(%d %d
,k,n);为什么答案是1,k++&&n++>2中'>'的优先级不是高于“&&”么?为什么不会先算n++>2
while循环几次?如题 int k=0; while(k=1)k++;
main() { int k=5,n=0; while(k>0) { switch(k) { default :break; case 1 :n+=k; case 2 :case 3 :n+main(){ int k=5,n=0;while(k>0){ switch(k){ default :break;case 1 :n+=k;case 2 :case 3 :n+=k;}k--;}printf(%d
,n);} 我想知道 结果 7 是怎么算出
C语言的一道提void primenum(int m,int k,int array[]){ int value = m+1;int half,n = 0,i;while(1){ half = value/2;for (i=2; i half){ array[n] = value;n++;}if (n >= k)break;value++;}}这个是求数字m之后k个素数的程序,我就不是很明
#include void mian() { int n; n=0; while(n
#include void main() { int k=5,n=0; while(k>0) {switch(k) {default : break; case 1:n+=k;
main() { char s[80]; int n=0,k=0; scanf(%s,s);while( );{if( )k=k+1,n++;}print(count-%d,k)}