在△ABC中,已知角A,B,C的对边分别为a,b,c已知(cosA-2cosC)/cosB=(2c-a)/b (1)求sinC/sinA的值 (2)若cosB=1/4,△ABC的周长为5,求b的长.需要详解
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![在△ABC中,已知角A,B,C的对边分别为a,b,c已知(cosA-2cosC)/cosB=(2c-a)/b (1)求sinC/sinA的值 (2)若cosB=1/4,△ABC的周长为5,求b的长.需要详解](/uploads/image/z/3653329-49-9.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5%E8%A7%92A%2CB%2CC%E7%9A%84%E5%AF%B9%E8%BE%B9%E5%88%86%E5%88%AB%E4%B8%BAa%2Cb%2Cc%E5%B7%B2%E7%9F%A5%28cosA-2cosC%29%2FcosB%3D%282c-a%29%2Fb+%281%29%E6%B1%82sinC%2FsinA%E7%9A%84%E5%80%BC+%EF%BC%882%EF%BC%89%E8%8B%A5cosB%3D1%2F4%2C%E2%96%B3ABC%E7%9A%84%E5%91%A8%E9%95%BF%E4%B8%BA5%2C%E6%B1%82b%E7%9A%84%E9%95%BF.%E9%9C%80%E8%A6%81%E8%AF%A6%E8%A7%A3)
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