已知a+b=2,求(a²-b²)²-8(a²+b²)的值
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已知a+b=2,求(a²-b²)²-8(a²+b²)的值
已知a+b=2,求(a²-b²)²-8(a²+b²)的值
已知a+b=2,求(a²-b²)²-8(a²+b²)的值
原式=(a+b)²(a-b)²-8(a²+b²)
=4(a²-2ab+b²)-8a²-8b²
=4a²-8ab+4b²-8a²-8b²
=-4a²-8ab-4b²
=-4(a+b)²
=-4*2²
=-16