已知函数f(x)=x-sinx,若x1,x2∈[-π/2,π/2]且f(x1)+f(x2)>0,则下列不等式中正确的是A x1>x2 Bx10 D x1+x2
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 14:02:34
![已知函数f(x)=x-sinx,若x1,x2∈[-π/2,π/2]且f(x1)+f(x2)>0,则下列不等式中正确的是A x1>x2 Bx10 D x1+x2](/uploads/image/z/3700658-2-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dx-sinx%2C%E8%8B%A5x1%2Cx2%E2%88%88%5B-%CF%80%2F2%2C%CF%80%2F2%5D%E4%B8%94f%28x1%29%2Bf%28x2%29%3E0%2C%E5%88%99%E4%B8%8B%E5%88%97%E4%B8%8D%E7%AD%89%E5%BC%8F%E4%B8%AD%E6%AD%A3%E7%A1%AE%E7%9A%84%E6%98%AFA+x1%3Ex2+Bx10+D+x1%2Bx2)
xőN@_4LSui-51qD6,^bE%Mjb(;93[8` ƭq39W/Ⱥ.Xo1Jc)vqi۫h(>ֈ_*US,MWX*ˮXV
M"5}cW{rB_WF1#xoBlD7wBA|N|H?OٽLx+PiȬͥ VmV$V? t8[A#.MV@/\DF]qpb^[$wnpQ6PNM9V~WyJx2Uun$0