在三角形ABC中,角A,B,C所对应的边分别为a,b,c,且cosA=1/3(1)求{sin[(B+C)/2]}^2+cos2A的值(2)若a=√3,求bc的最大值
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![在三角形ABC中,角A,B,C所对应的边分别为a,b,c,且cosA=1/3(1)求{sin[(B+C)/2]}^2+cos2A的值(2)若a=√3,求bc的最大值](/uploads/image/z/3716142-6-2.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92A%2CB%2CC%E6%89%80%E5%AF%B9%E5%BA%94%E7%9A%84%E8%BE%B9%E5%88%86%E5%88%AB%E4%B8%BAa%2Cb%2Cc%2C%E4%B8%94cosA%3D1%2F3%EF%BC%881%EF%BC%89%E6%B1%82%7Bsin%5B%28B%2BC%29%2F2%5D%7D%5E2%2Bcos2A%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E8%8B%A5a%3D%E2%88%9A3%2C%E6%B1%82bc%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC)
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