一个锐角三角形ABC的三条角平分线交与O点,过O作OE垂直BC于E,AD平分∠BAC交BC于点D 求证;∠BOD=∠COE 求EOC+OCE=90BAC+ACB+ABC=180 都除以2既是OBA+BAO+OCE=90而BOD=OBA+BAO得证擦 自己想起来了 快10年没碰了
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![一个锐角三角形ABC的三条角平分线交与O点,过O作OE垂直BC于E,AD平分∠BAC交BC于点D 求证;∠BOD=∠COE 求EOC+OCE=90BAC+ACB+ABC=180 都除以2既是OBA+BAO+OCE=90而BOD=OBA+BAO得证擦 自己想起来了 快10年没碰了](/uploads/image/z/3716422-70-2.jpg?t=%E4%B8%80%E4%B8%AA%E9%94%90%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%89%E6%9D%A1%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E4%B8%8EO%E7%82%B9%2C%E8%BF%87O%E4%BD%9COE%E5%9E%82%E7%9B%B4BC%E4%BA%8EE%2CAD%E5%B9%B3%E5%88%86%E2%88%A0BAC%E4%BA%A4BC%E4%BA%8E%E7%82%B9D+%E6%B1%82%E8%AF%81%EF%BC%9B%E2%88%A0BOD%3D%E2%88%A0COE+%E6%B1%82EOC%2BOCE%3D90BAC%2BACB%2BABC%3D180+%E9%83%BD%E9%99%A4%E4%BB%A52%E6%97%A2%E6%98%AFOBA%2BBAO%2BOCE%3D90%E8%80%8CBOD%3DOBA%2BBAO%E5%BE%97%E8%AF%81%E6%93%A6+%E8%87%AA%E5%B7%B1%E6%83%B3%E8%B5%B7%E6%9D%A5%E4%BA%86+%E5%BF%AB10%E5%B9%B4%E6%B2%A1%E7%A2%B0%E4%BA%86)
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