The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without stopping.Dudi,s speed is 1.5 times Gani,s speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.the two boys meet for the f

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The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without stopping.Dudi,s speed is 1.5 times Gani,s speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.the two boys meet for the f
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The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without stopping.Dudi,s speed is 1.5 times Gani,s speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.the two boys meet for the f
The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without stopping.Dudi,s speed is 1.5 times Gani,s speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.the two boys meet for the first time at 800 meters away from B.How far are the bots from A when they meet for the second time?翻译并解答,事后必有重谢!

The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without stopping.Dudi,s speed is 1.5 times Gani,s speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.the two boys meet for the f
两个男孩,Dudi和Gani,在A和B两点之间以不变的速度来回奔跑.Dudi的速度是Gani的1.5倍.Dudi从A点出发往B点跑,Gani从B点出发往A点跑.两人同时起跑.两人第一次相遇是在离B点800米处.问题:当他们第二次相遇时,他们离A点的距离是多少?
两人第一次相遇时距B点800米,也就是说Gani跑了800米,又因为Dudi的速度是Gani的1.5倍,所以这时Dudi跑了800*1.5=1200米,即两人第一次相遇的地方距A点1200米,也就是说A、B两点相距800+1200=2000米
从第一次相遇到第二次相遇,两人加起来总共要跑的长度是A、B两点距离的2倍,即4000米.又因为Dudi速度是Gani的1.5倍,所以Dudi要跑的长度也是Gani的1.5倍,即Dudi要跑2400米,Gani要跑1600米.
现在我们看看Gani的1600米是怎么跑的.首先他要从两人第一次相遇的地方继续向A点跑,然后从A点折回向B点跑.因为两人第一次相遇的地方距离A点1200米,所以两人第二次相遇的地方距离A点1600-1200=400米.
答案是400米