在平面直角坐标系中,点B(-3,0),点C(0,2),将线段CB顺时针旋转90°,点B的对应点正好落在双曲线y=k/x(x.0),求函数y=k/x的解析式,2.取AC中点E,连接BE,CF垂直于BE交AB于点F,求证角AEF等于角BEC
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/05 05:36:23
![在平面直角坐标系中,点B(-3,0),点C(0,2),将线段CB顺时针旋转90°,点B的对应点正好落在双曲线y=k/x(x.0),求函数y=k/x的解析式,2.取AC中点E,连接BE,CF垂直于BE交AB于点F,求证角AEF等于角BEC](/uploads/image/z/3746313-9-3.jpg?t=%E5%9C%A8%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E7%82%B9B%28-3%2C0%29%2C%E7%82%B9C%280%2C2%29%2C%E5%B0%86%E7%BA%BF%E6%AE%B5CB%E9%A1%BA%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0%2C%E7%82%B9B%E7%9A%84%E5%AF%B9%E5%BA%94%E7%82%B9%E6%AD%A3%E5%A5%BD%E8%90%BD%E5%9C%A8%E5%8F%8C%E6%9B%B2%E7%BA%BFy%3Dk%2Fx%28x.0%29%2C%E6%B1%82%E5%87%BD%E6%95%B0y%3Dk%2Fx%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%2C2.%E5%8F%96AC%E4%B8%AD%E7%82%B9E%2C%E8%BF%9E%E6%8E%A5BE%2CCF%E5%9E%82%E7%9B%B4%E4%BA%8EBE%E4%BA%A4AB%E4%BA%8E%E7%82%B9F%2C%E6%B1%82%E8%AF%81%E8%A7%92AEF%E7%AD%89%E4%BA%8E%E8%A7%92BEC)
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