(x-3)(x-2)(x-5)≥0,
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 04:30:42
![(x-3)(x-2)(x-5)≥0,](/uploads/image/z/3762571-67-1.jpg?t=%EF%BC%88x-3%EF%BC%89%28x-2%29%28x-5%EF%BC%89%E2%89%A50%2C)
x){BN
]#M a
d?\jcTOZΆ
XDIS<;16`$;[IH)Tٚ*m 2@Jƶ$ N
(x-3)(x-2)(x-5)≥0,
(x-3)(x-2)(x-5)≥0,
(x-3)(x-2)(x-5)≥0,
x≥3,x≥2,x≥5 取x≥5
x-3>=0,x-2>=0,x-5>=0 x>=5 x-2>=0,x-3<=0,x-5<=0 2<=x<=3
3≤|8-x| |x+1|>2-x |x+3|7|x+1| x^2-6|x|+9>0 |x-1|+|x+2|≥5 (1)方法
(x-3)(x-2)(x-5)≥0,
解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1
1.-X^2+X≥3x+12.x(x+9)≤3(x-3)3.X^2-2x<2X^2+2解题格式一定要写好哦4.-x+1/2x+5≥05.(m-2)x>1-m6.X^2-(a-3)X-3a<07.X^2-(a+1/a)x+1>0
已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2)
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
解方程(x-2)X(x的平方-6x-9)=x(x-5)X(x-3)
300字读后感 2篇 俄把格式说一下吧:《xxxx》(写题目)主要内容:x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x(写那篇文章的主要内容)思考分析:x x x
1.判别下列函数的奇偶数性:(1) f(x)=|x+1|+|x-1|;(2)f(x)=3/x²;(3)f(x)=x+1/x;(4)f(x)=x/1.x²;(5)x∈[-1,3]2.f(x)=(x+1)(x+a)/x为奇函数,则a=__________.3.已知函数f(x)(x∈R)是奇函数,且x≥0时,f(x)
不等式|(x+3)/x|>(x+3)/x,不等式(x²-9)/(x-2)>0
x(x平方-1)+2X平方(X+1)-3X(2X-5)帮个忙
化简(x+2)(x的平方-6x-9)-(x-5)(x-3)x
分式不等式解法(x-1)(x-3)(x+5)/(x+2)(x-3)(x-1)>0x-1)(x-3)(x+5)/(x+2)(x-3)(x-6)>0
一元二次方程解答!x(5x+4)=5x+44x^2-45=31x-3x^2+22x-24=0(x+8)(x+1)= -12(3x+2)(x+3)=x+14
1、1/2x=2/x+32、x/x+1=(2x/3x+3)+13、2/x-1=4/x²-14、5/x²+x-1/x²-x=0
先化简,再求值 [2/3x - 2/x+y(x+y/3x -x-y)]*x/x-y,其中5x+3y=0
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
求和:Sn=1+3x+5x*x+7x*x*x+……+(2n-1)x^n-1 (x不为0和1)