方程2y²+3=7y配方后,得2(y-7/4)²=____.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 14:17:08
![方程2y²+3=7y配方后,得2(y-7/4)²=____.](/uploads/image/z/3763237-13-7.jpg?t=%E6%96%B9%E7%A8%8B2y%26%23178%3B%2B3%3D7y%E9%85%8D%E6%96%B9%E5%90%8E%2C%E5%BE%972%28y-7%2F4%29%26%23178%3B%3D____.)
x){6mFjʆƶ/[{O'<7HR\D"oz6IEi/N#S}0OvR@1BYgÓKႺ@!G
Sm!zQ
5zPHRN[d Q``$A}e7\5I 1
方程2y²+3=7y配方后,得2(y-7/4)²=____.
方程2y²+3=7y配方后,得2(y-7/4)²=____.
方程2y²+3=7y配方后,得2(y-7/4)²=____.
25/8
因为 2y²+3=7y 所以 2y²-7y =—3=
2(y-7/4)²=2(y²-7y/2+49/16)=2y²-7y +49/8
=—3+49/8
=25/8
方程2y²+3=7y配方后,得2(y-7/4)²= 25/8
八分之二十五