已知g(x)=(a+1)的x-2方+1 (a>0)的图像恒过定点A(2,2)且点A在函数f(x)=log√3(x+a)的图像上.g(x)=y=2^(x-2)+12^(x-2)=y-1x-2=log2(y-1) --------------①-----------这步是怎么得到的 x=log2(y-1)+2-------------②----------
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![已知g(x)=(a+1)的x-2方+1 (a>0)的图像恒过定点A(2,2)且点A在函数f(x)=log√3(x+a)的图像上.g(x)=y=2^(x-2)+12^(x-2)=y-1x-2=log2(y-1) --------------①-----------这步是怎么得到的 x=log2(y-1)+2-------------②----------](/uploads/image/z/3777657-33-7.jpg?t=%E5%B7%B2%E7%9F%A5g%28x%29%3D%28a%2B1%29%E7%9A%84x-2%E6%96%B9%2B1+%28a%EF%BC%9E0%29%E7%9A%84%E5%9B%BE%E5%83%8F%E6%81%92%E8%BF%87%E5%AE%9A%E7%82%B9A%EF%BC%882%2C2%EF%BC%89%E4%B8%94%E7%82%B9A%E5%9C%A8%E5%87%BD%E6%95%B0f%28x%29%3Dlog%E2%88%9A3%EF%BC%88x%2Ba%EF%BC%89%E7%9A%84%E5%9B%BE%E5%83%8F%E4%B8%8A.g%28x%29%3Dy%3D2%5E%28x-2%29%2B12%5E%28x-2%29%3Dy-1x-2%3Dlog2%28y-1%29+--------------%E2%91%A0-----------%E8%BF%99%E6%AD%A5%E6%98%AF%E6%80%8E%E4%B9%88%E5%BE%97%E5%88%B0%E7%9A%84+x%3Dlog2%28y-1%29%2B2-------------%E2%91%A1----------)
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