已知等差数列{an}的首项为a,公差为b,且不等式ax^2-3x+2>0的解集为(-无穷,1)∪(b,+无穷)若数列{bn}满足bn=an*(2^n),求数列bn前n项和Tn.
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![已知等差数列{an}的首项为a,公差为b,且不等式ax^2-3x+2>0的解集为(-无穷,1)∪(b,+无穷)若数列{bn}满足bn=an*(2^n),求数列bn前n项和Tn.](/uploads/image/z/3778602-42-2.jpg?t=%E5%B7%B2%E7%9F%A5%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%A6%96%E9%A1%B9%E4%B8%BAa%2C%E5%85%AC%E5%B7%AE%E4%B8%BAb%2C%E4%B8%94%E4%B8%8D%E7%AD%89%E5%BC%8Fax%5E2-3x%2B2%3E0%E7%9A%84%E8%A7%A3%E9%9B%86%E4%B8%BA%28-%E6%97%A0%E7%A9%B7%2C1%29%E2%88%AA%28b%2C%2B%E6%97%A0%E7%A9%B7%29%E8%8B%A5%E6%95%B0%E5%88%97%7Bbn%7D%E6%BB%A1%E8%B6%B3bn%3Dan%2A%282%5En%29%2C%E6%B1%82%E6%95%B0%E5%88%97bn%E5%89%8Dn%E9%A1%B9%E5%92%8CTn.)
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