如图(1),BD、CE分别是△ABC的外角平分线,过点A作AF⊥BD,AG⊥CE,垂足分别为F、G,连结FG,延长AF、AG,与直线BC相交.(1)求证:FG= (AB+BC+AC)(2)若BD、CE分别是△ABC的内角平分线,如图(2);BD为
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![如图(1),BD、CE分别是△ABC的外角平分线,过点A作AF⊥BD,AG⊥CE,垂足分别为F、G,连结FG,延长AF、AG,与直线BC相交.(1)求证:FG= (AB+BC+AC)(2)若BD、CE分别是△ABC的内角平分线,如图(2);BD为](/uploads/image/z/3782086-70-6.jpg?t=%E5%A6%82%E5%9B%BE%EF%BC%881%EF%BC%89%2CBD%E3%80%81CE%E5%88%86%E5%88%AB%E6%98%AF%E2%96%B3ABC%E7%9A%84%E5%A4%96%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2C%E8%BF%87%E7%82%B9A%E4%BD%9CAF%E2%8A%A5BD%2CAG%E2%8A%A5CE%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E4%B8%BAF%E3%80%81G%2C%E8%BF%9E%E7%BB%93FG%2C%E5%BB%B6%E9%95%BFAF%E3%80%81AG%2C%E4%B8%8E%E7%9B%B4%E7%BA%BFBC%E7%9B%B8%E4%BA%A4.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9AFG%3D+%EF%BC%88AB%2BBC%2BAC%EF%BC%89%EF%BC%882%EF%BC%89%E8%8B%A5BD%E3%80%81CE%E5%88%86%E5%88%AB%E6%98%AF%E2%96%B3ABC%E7%9A%84%E5%86%85%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2C%E5%A6%82%E5%9B%BE%EF%BC%882%EF%BC%89%EF%BC%9BBD%E4%B8%BA)
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