函数f(x)=(1/3)x³-f‘(1)x²+2x+5则f’(2)为多少?
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函数f(x)=(1/3)x³-f‘(1)x²+2x+5则f’(2)为多少?
函数f(x)=(1/3)x³-f‘(1)x²+2x+5则f’(2)为多少?
函数f(x)=(1/3)x³-f‘(1)x²+2x+5则f’(2)为多少?
f(x)=(1/3)x³-f‘(1)x²+2x+5
f'(x)=x²-2f'(1)x+2
f'(1)=1-2f'(1)+2
f'(1)=1
f'(x)=x²-2x+2
f'(2)=4-4+2=2