换元法求定积分x^0.5/(2-x^0.5)dx
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 03:37:10
![换元法求定积分x^0.5/(2-x^0.5)dx](/uploads/image/z/3819667-67-7.jpg?t=%E6%8D%A2%E5%85%83%E6%B3%95%E6%B1%82%E5%AE%9A%E7%A7%AF%E5%88%86x%5E0.5%2F%282-x%5E0.5%29dx)
xJA_E@wƙٯØuۭ͝HB)"&"
ɺJ.2
zhWKo3;XAqzٕtx"ۊTXv"X*x5QF}@
8|75І!@qBLXvs
9X!G5. `jiu2\e5C\\UvQ폅 %D54lH.nBLVd-Sv>X :hFuD'oeDe3"9cܺgUk;^GuU+߆qN'M4:FD^4nY hu1/{
换元法求定积分x^0.5/(2-x^0.5)dx
换元法求定积分x^0.5/(2-x^0.5)dx
换元法求定积分x^0.5/(2-x^0.5)dx
令根号x=t
原式等于2t^2/(2-t)dt
2t^2=2t^2-8+8=2(t-2)(t+2)+8
再带入原试=-2(t+2)dt+8/(2-t)dt
后面就带进去算一下就可以了