解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1x+y/6+x-y/10=3 ①x+y/6+y-x/10=-1 ②

来源：学生作业帮助网编辑：作业帮时间：2024/07/07 05:54:51

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解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1x+y/6+x-y/10=3 ①x+y/6+y-x/10=-1 ②
解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1
x+y/6+x-y/10=3 ①
x+y/6+y-x/10=-1 ②

解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1x+y/6+x-y/10=3 ①x+y/6+y-x/10=-1 ②
①－②可得：x-y/10－y-x/10=4
x-y／5＝4
x-y＝20 ——③
①＋②可得：x+y/3=2
x+y=6 ——④
由③④可得：x=13,y=－7

x+y/6+x-y/10=3 ①
x+y/6+y-x/10=-1 ②
(x+y)/6+(x-y)/10=3
(x+y)/6-(x-y)/10=-1
设(x+y)/6=a (x-y)/10=b
则a+b=3 a-b=-1
a=1 b=2
(x+y)/6=1 x+y=6
(x-y)/10=2 x-y=20
x=13 y=-7

1式-2式=x-y/10-y-x/10=4 y 消掉 x=20
1式+2式=2（x+y）/6=2 y =-14

你这里都是一次的？打错了吧

就是二元一次方程吗

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