这个四元一次方程该怎么解?a+2b+3c+6d=1002a+b+3c+6d=2002a+2b+c+6d=3002a+2b+3c+d=400
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 21:19:42
![这个四元一次方程该怎么解?a+2b+3c+6d=1002a+b+3c+6d=2002a+2b+c+6d=3002a+2b+3c+d=400](/uploads/image/z/3832572-12-2.jpg?t=%E8%BF%99%E4%B8%AA%E5%9B%9B%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%E8%AF%A5%E6%80%8E%E4%B9%88%E8%A7%A3%3Fa%2B2b%2B3c%2B6d%3D1002a%2Bb%2B3c%2B6d%3D2002a%2B2b%2Bc%2B6d%3D3002a%2B2b%2B3c%2Bd%3D400)
xTn@m@ЍďupHQM! Q!!aBV%xY!bEn*s;a˥Qxt׳v:ǣ~^|qʔ4Km)`UQ4S➖x@&= (E{rZ!! -RoT6mɧc8 W$[Q
#5r1R_&yjFs_"988LW9?iSZE4MNРhq Ib'6KϬLѺT+%>gsԂs`8MHsJYeV)Ҙ
PKYH `
6ZldTsCoR_JP)uߖץt]ɽ2i<؊ƕik.b*̓f"<8&NhdtCT"2D$j_wA5wH"zTNzs
[