已经tanA=-1/2,则sin^2A+sinAcosA-cos^2A的值为多少?
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已经tanA=-1/2,则sin^2A+sinAcosA-cos^2A的值为多少?
已经tanA=-1/2,则sin^2A+sinAcosA-cos^2A的值为多少?
已经tanA=-1/2,则sin^2A+sinAcosA-cos^2A的值为多少?
tanA=-1/2
SINA/COSA=-1/2
COSA=-2SINA,
(COSA)^2+(SINA)^2=1 (COSA)^2=1-(SINA)^2
(-2SINA)^2+(SINA)^2=1
(SINA)^2=1/5
代入:
sin^2A+sinAcosA-cos^2A
=(SINA)^2+SINA*(-2SINA)-(-2SINA)^2
=(SINA)^2-2(SINA)^2-4(SINA)^2
=-5(SINA)^2
=-1
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