已知函数F(x)=X^3+ax^2+2 (a∈R) 且曲线Y=F(x)在点(2,f(2))处的切线斜率为0 求1.F(x)在闭区间(-1,3)上的最大值和最小值.2.a的值
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![已知函数F(x)=X^3+ax^2+2 (a∈R) 且曲线Y=F(x)在点(2,f(2))处的切线斜率为0 求1.F(x)在闭区间(-1,3)上的最大值和最小值.2.a的值](/uploads/image/z/3843848-56-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0F%EF%BC%88x%EF%BC%89%3DX%5E3%2Bax%5E2%2B2+%EF%BC%88a%E2%88%88R%29+%E4%B8%94%E6%9B%B2%E7%BA%BFY%3DF%EF%BC%88x%EF%BC%89%E5%9C%A8%E7%82%B9%EF%BC%882%2Cf%282%29%EF%BC%89%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%9C%E7%8E%87%E4%B8%BA0+%E6%B1%821.F%EF%BC%88x%EF%BC%89%E5%9C%A8%E9%97%AD%E5%8C%BA%E9%97%B4%EF%BC%88-1%2C3%EF%BC%89%E4%B8%8A%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC.2.a%E7%9A%84%E5%80%BC)
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