△ABC的顶点分别是A(2,1)B(4,3) C(3,-2) ∠A的平分线所在的直线方程是直线AB的方程为:y=2x-5直线AC的方程为:y=-x+1设∠BAC的平分线为:y=kx+b因为经过点A所以-1=2k+b∴ b=-1-2k………………①角平分
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![△ABC的顶点分别是A(2,1)B(4,3) C(3,-2) ∠A的平分线所在的直线方程是直线AB的方程为:y=2x-5直线AC的方程为:y=-x+1设∠BAC的平分线为:y=kx+b因为经过点A所以-1=2k+b∴ b=-1-2k………………①角平分](/uploads/image/z/3860745-33-5.jpg?t=%E2%96%B3ABC%E7%9A%84%E9%A1%B6%E7%82%B9%E5%88%86%E5%88%AB%E6%98%AFA%EF%BC%882%2C1%EF%BC%89B%284%2C3%29+C%283%2C-2%29+%E2%88%A0A%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E6%89%80%E5%9C%A8%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B%E6%98%AF%E7%9B%B4%E7%BA%BFAB%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%EF%BC%9Ay%3D2x-5%E7%9B%B4%E7%BA%BFAC%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%EF%BC%9Ay%3D-x%2B1%E8%AE%BE%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%B8%BA%EF%BC%9Ay%3Dkx%2Bb%E5%9B%A0%E4%B8%BA%E7%BB%8F%E8%BF%87%E7%82%B9A%E6%89%80%E4%BB%A5-1%3D2k%2Bb%E2%88%B4+b%3D-1-2k%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6%E2%91%A0%E8%A7%92%E5%B9%B3%E5%88%86)
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