已知(ab-2)的平方+(b-1)的平方=0,求1/ab+1/(a+1)x(b+1)+1/(a+2)x(b+2)+…+1/(a+100)x(b+100)的值.
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![已知(ab-2)的平方+(b-1)的平方=0,求1/ab+1/(a+1)x(b+1)+1/(a+2)x(b+2)+…+1/(a+100)x(b+100)的值.](/uploads/image/z/3910644-36-4.jpg?t=%E5%B7%B2%E7%9F%A5%28ab-2%29%E7%9A%84%E5%B9%B3%E6%96%B9%2B%28b-1%29%E7%9A%84%E5%B9%B3%E6%96%B9%3D0%2C%E6%B1%821%2Fab%2B1%2F%28a%2B1%29x%28b%2B1%29%2B1%2F%28a%2B2%29x%28b%2B2%29%2B%E2%80%A6%2B1%2F%28a%2B100%29x%28b%2B100%29%E7%9A%84%E5%80%BC.)
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