用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]比人还在自学期间,越清楚越明白越好~
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 16:20:57
x){>eųEOwM}ںLO04Ʊ`cM#QSbsVh_tgs濜EŶg;Z-b{>s/t:"}rm%J;z{HFDJ
X-r< boUe˙$A}m=
w%ppg@m*.eA
M &p
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]比人还在自学期间,越清楚越明白越好~
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]
比人还在自学期间,越清楚越明白越好~
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]比人还在自学期间,越清楚越明白越好~
[log(4)3+log(8)3][log(3)2+log(9)2]
=[1/2log(2)3+1/3log(2)3]*[log(3)2+1/2log(3)2]
=5/6log(2)3*3/2log(3)2
=5/4
=[1/2log(2)3+1/3log(2)3]*[log(3)2+1/2log(3)2]
=5/6log(2)3*3/2log(3)2
=5/4
[log(4)3+log(8)3][log(3)2+log(9)2]
=[2log(2)3+3log(2)3][log(3)2+2log(3)2]
=5log(2)3*3log(3)2
=5log(2)3*3/log(2)3
=15
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]比人还在自学期间,越清楚越明白越好~
用换底公式求log(2)25乘log(3)4乘log(5)9的值
log(4)7 * log(49)25 * log(125)64 用换底公式怎样计?
简化2log (x + 4) – log(2x + 8) + log(x - 2)谢谢~
log(75)10-log(3)10+log(4)10
4^[log(2)3+log(4)8]
log(2)9log(3)4等于
log(27)16/log(3)4=
log(2)9×log(3)4
log(8)9 / log(2)3 这要用什么公式啊`?
化简log(2)3 * log(3)4 * log(4)7 *log(7)16
化简:(log^3 2+log^9 2)(log^4 3+log^8 3)
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路
log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃....
log
log
log