大一高数求解.lim {(1+n)[In(1+n)-In(n)]}.n趋向无穷.

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 19:19:07
大一高数求解.lim {(1+n)[In(1+n)-In(n)]}.n趋向无穷.
x){d /Wx6uóM//U0ӌӺ@:O3V/Ŷ&>z6IE_`gC7Uk=jc&vm`e(Ҟy`Z?CmC

大一高数求解.lim {(1+n)[In(1+n)-In(n)]}.n趋向无穷.
大一高数求解.lim {(1+n)[In(1+n)-In(n)]}.n趋向无穷.

大一高数求解.lim {(1+n)[In(1+n)-In(n)]}.n趋向无穷.
lim(n→∞) {(1+n)[In(1+n)-In(n)]
=lim(n→∞) (1+n)In[(1+n)/n]
=lim(n→∞) (1+n)In[1+1/n)
=lim(n→∞) (1+n)*1/n
=1

ln(1+n)-lnn=ln(1+1/n)
然后令t->0+ t=1/n
化成0/0型,就可以用洛必达法则做了