设全集U={3,4,a²+2a-3},集合A={a+1,2a},CUA={5},求a的值,
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设全集U={3,4,a²+2a-3},集合A={a+1,2a},CUA={5},求a的值,
设全集U={3,4,a²+2a-3},集合A={a+1,2a},CUA={5},求a的值,
设全集U={3,4,a²+2a-3},集合A={a+1,2a},CUA={5},求a的值,
a²+2a-3=5;
a²+2a-8=0;
(a+4)(a-2)=0;
a=-4,a+1=-3,2a=-8;符合;
a=2,a+1=3,2a=6;a+1和3相同,所以不符合;
所以a=-4;