如图,AB=AE.BC=ED.
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如图,AB=AE.BC=ED.
如图,AB=AE.BC=ED.
如图,AB=AE.BC=ED.
连接AC,AD.
因为AB=AE,BC=ED,角B=角E
所以三角形ABC全等于三角形AED
所以AC=AD
又因为AD垂直于DC
所以CF=DF (等腰三角形三线合一性质0
如图,AB=AE.BC=ED.
如图,AB=AE.BC=ED.
如图,AE⊥AB,BC⊥AB,CD⊥ED,ED=DC.求证:AE+BC=AB.
已知:如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC.求证:ED⊥AC.
已知:如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证:ED⊥AC
已知,如图,ae垂直ab,bc垂直ab,ae=ab,ed=ac 求证 ed垂直ac
如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC,求证:ED⊥AC
已知,如图,AB⊥BC,AE⊥ED,AB=AE,
已知:如图,AB⊥BC,AE⊥ED,AB=AE,
如图AB=AE,AC=AD,ED=BC,AE⊥AB 求证BC⊥DE
已知:如图,AB⊥BC,AE⊥ED,AB=AE∠ACD=∠ADC.求证:BC=ED请写过程,谢谢!
已知如图,AB⊥BC,AE⊥ED,AB=AE,∠ACD=∠ADC.求证:BC=ED
蟹蟹!2.如图,已知AB⊥BC,AE⊥ED,AB=BC,∠DCE=135°,说明AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明:AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明:AE=ED
如图,已知:AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证:ED⊥BC.
如图,已知AB=AE,BC=ED,AC=AD,求证:BE平行CD